int(0)^2 sqrt(a^2 - x^2) dx...

`int_(0)^2 sqrt(a^2 - x^2) dx`

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The value of the expression (int_0^a x^4(sqrt(a^2-x^2)))/(int_0^a x^2(sqrt(a^2-x^2))) dx is

int_(0)^(a)sqrt(a^(2)-x^(2))dx=

int_(0)^(2) sqrt(2-x)dx .

I=int_(0)^(2)x sqrt(4-x^(2))dx

Evaluate :int_(0)^(2)sqrt(4-x^(2))dx

Compute the integrals I = int_(0)^(2a) sqrt(2 a x - x^(2)) dx

int_(0)^(a)x sqrt(a^(2)-x^(2))dx

int_(0)^(a)dx/(sqrt(a^2-x^2))

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