A particle of mass `1kg` is moving along a circle of radius `2 m`.If centripetal acceleration of particle varies as `a_(c)=3t^(2)`,where all quantities are in SI units. The average power delivered to the particle in first `10s` in watt is

A particle is moving at uniform speed 2 ms^(-1) along a circle of radius 0.5m .The centripetal acceleration of particle is

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a_(c) is varying with time t as a_(c) = k^(2)rt^(2) , where k is a constant. The power delivered to the particle by the forces acting on it is :

A particle of mass m impves along a horzontal circle of radius R such that normal acceleration of particle varies with time as a_(n)=kt^(2). where k is a constant. Power developed by total at time t is

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a_(c) is varying with the time t as a_(c)=k^(2)r^(3)t^(4) where k is a constant. The power delivered to the particle by the forces acting on it is

A particle of mass M is moving in a circle of fixedradius R in such a way that its centripetal accelerationn at time t is given by n^2Rt^2 where n is a constant. The power delivered to the particle by the force acting on it, it :

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle is moving along a circle of radius 3 m .If its centripetal acceleration is 3ms^(-2) , its angular velocity in rad s^(-1) is

A particle is moving on a circular path of radius 0.3 m and rotaing at 1200 rpm. The centripetal acceleration of the particle