`tan(A+B)=tan (pi/4)`

Prove that: (tan(pi/4+A)+tan(pi/4-A))/(tan(pi/4+A)-tan(pi/4-A))="cosec"2A

If A,B,C are angles of a triangle, prove that (tan (B+C)+tan(C+A)+tan(A+B))/(tan (pi-A)+tan(2pi-B)+tan(3pi-C))=1 .

Prove that: tan(pi/4+A)+tan(pi/4-A) = 2sec2A

Evaluate each of the following: tan^(-1)(tan(9pi)/4) (ii) tan^(-1)(tan1) (iii) tan^(-1)(tan2)

(sec A + tan A)/(sec A-tanA) = tan^2(pi/4 + A/2) prove that

Find the value of tan^(-1)(tan((3pi)/4))

Find the value of tan^(-1)(tan((3pi)/4))

Solve : tan ((pi)/(4)+ theta) + tan ((pi)/(4) - theta) = 4

cos[tan^(-1){tan((15pi)/4)}]

If A+B+C=pi , prove that : tan( A/2) tan (B/2) + tan (B/2 )tan (C/2)+ tan( C/2) tan (A/2) =1