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If y=2^(2^x) then frac{dy}{dx}=...

If `y=2^(2^x)` then `frac{dy}{dx}=`

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dy/dx = frac{2x+y}{x}

If 2^(x)+2^(y)=2^(x+y) then (dy)/(dx) is equal to

If y=x^(x^(2)), then (dy)/(dx) equals

dy/dx = frac{x^2+y^2}{2x^2}

If y=(x^(2))/((x+1))"then"(dy)/(dx)"is":-

dy/dx + frac{1-2x}{x^2} y = 1

dy/dx = frac{x^2+y^2+1}{2xy}

y= (a^2+x^2)/(sqrt(a^2-x^2)) then dy/dx=

x^2 frac{dy}{dx} + (1-2x) y = x^2

x frac{dy}{dx} = y - xcos^2 frac{y}{x}