`y=(u+(1)/(u))^(3)` ,find `(dy)/(du)`

If y=(1)/(4)u^(4),u=(2)/(3)x^(3)+5 , then (dy)/(dx)=

U=x^y find (dU)/dx

If quad tan((1)/(2)(cos^(-1))(1-u^(2))/(1+u^(2))+(1)/(2)(sin^(-1))(2u)/(1+u^(2))) and x=(2u)/(1-u^(2)) then (dy)/(dx)

u=(x^(2)-y^(2))/(x^(2)+y^(2)) find d(u)/(dx)?

If y = f(u) is a differentiable functions of u and u = g(x) is a differentiable functions of x such that the composite functions y = f[g(x) ] is a differentiable functions of x then (dy)/(dx) = (dy)/(du) . (du)/(dx) Hence find (dy)/(dx) if y = sin ^(2)x

Given y=f(u) and u=g(x) Find (dy)/(dx) if y=2u^(3),u=8x-1

Given y = f(u) and u = g(x). Find (dy)/(dx) . y = sin u, u = 3x + 1

If x=sqrt (1+u^(2)),y =log (1+u^(2) ) ,then (dy)/(dx) =

If y=tan[(1)/(2)cos^-1((1-u^(2))/(1+u^(2)))+(1)/(2)sin^(-1)((2u)/(1+u^(2)))]" and "x=(2u)/(1-u^(2))," then: "(dy)/(dx)=

If variables x and y are related by the equation x=int_(0)^(y)(1)/(sqrt(1+9u^(2))) du, then (dy)/(dx) is equal to