Simplify `(acostheta)/(bsintheta)+(bsintheta)/(acostheta)`

Simplify (1-costheta)/sintheta

Simplify (1-costheta)/sintheta

i) If acostheta+bsintheta=m and asintheta-bcostheta=n , then prove that: a^(2)+b^(2)=m^(2)+n^(2)

If x/acostheta+y/bsintheta=1,x/asintheta-y/bcostheta=1 , then eliminate theta .

If acostheta+bsintheta=m and asintheta-bcostheta=n , then show that a^(2)+b^(2)=m^(2)+n^(2) .

Evaluate (a+bcostheta)^2+(bsintheta)^2

Find the equation of the straight lines joining the points (acostheta_(1),asintheta_(1)) and (acostheta_(2),asintheta_(2)) .

If acostheta +bsin theta=pand a sin theta-b cos theta=q , then the relation between a , b , p and q is

Simplify (b+1)^3

If x=acostheta+bsintheta,y=asintheta-bcostheta , show : y^(2)(d^(2)y)/(dx^(2))-x(dy)/(dx)+y=0 .