Simplify `(sin^3theta+cos^3theta)/(sintheta+costheta)+(sin^3theta-cos^3theta)/(sintheta-costheta)`

(sin^(3)theta+cos^(3)theta)/(sintheta+costheta)+(sin^(3)theta-cos^(3)theta)/(sintheta-costheta)=

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

Prove (sin^3theta+cos^3theta)/(sintheta+costheta)=1-sinthetacostheta

costheta-cos2theta=sin3theta

The value of (sin^3theta+cos^3theta)/(sintheta+costheta) +sin theta cos theta is:

Prove that : (sintheta-costheta)/(sintheta+costheta)+(sintheta+costheta)/(sintheta-costheta)=(2)/(2sin^(2)theta-1)

The value of (sin^3 theta + cos^3 theta)/(sin theta+ costheta)+((cos^3 theta - sin^3 theta))/(cos theta - sin theta) is

(sintheta+sin2theta)/(1+costheta+cos2theta) =

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?

(sintheta+sin2theta)/(1+costheta+cos2theta)=?