If `y=1/(x+1) `,find `dy/dx`

y=1/(1+x) find dy/dx

y=x(x+1)^3 find dy/dx

x^4+y^x=1 find dy/dx

y=(x^2+1/x^2)^3 find dy/dx

If y=x^x+x^(1//x) , find (dy)/(dx)

y=sqrt((x^(2)+x+1)/(x^(2)-x+1)) find dy/dx

If y=tan^(-1)((1-x)/(1+x)) , find (dy)/(dx) .

If y=[(x^2+1)/(x+1)] , then find (dy)/(dx) .

Given that y= (3x -1)^(2) + (2x -1)^(3) , find (dy)/( dx) and the points on the curve for which (dy)/(dx)=0

(v) Let y= sqrt{(1+x)/(1-x)} find dy/dx