Simplify `(sin theta+cos theta)^(3)-(sin theta-cos theta)^(3)`

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Simplify (sin theta+cos theta+1)/(sin theta+cos theta-1)-(1+sin theta-cos theta)/(1-sin theta+cos theta)

(3cos theta+cos3 theta)/(3sin theta-sin3 theta)=

Simplify [(sin theta)/(cos theta)+(cos theta)/(sin theta)]^(2)

(3sin theta-sin3 theta)/(3cos theta+cos3 theta)=

Simplify cos theta[(cos theta,sin theta),(-sin theta,cos theta)]+sin theta[(sin theta,-cos theta),(cos theta,sin theta)]

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

if (sin theta-cos theta)/(sin theta+cos theta)=(sqrt(3)-1)/(sqrt(3)+1) then find the theta

If (sin theta+cos theta)/(sin theta-cos theta)=3 and theta is an acute angle, then the value of (3sin theta+4cos theta)/(8cos theta-3sin theta) is: यदि (sin theta+cos theta)/(sin theta-cos theta)=3 तो (3sin theta+4cos theta)/(8cos theta-3sin theta) का मान ज्ञात करें ।