Solve `int(sqrtx+1/sqrtx)^2dx`

int (1/sqrtx-sqrtx)dx

y= log(sqrtx+1/sqrtx)

"int5sqrtx dx

If int (sqrtx)^5/((sqrtx)^7+x^6) dx= alog(x^k/(1+x^k))+c then a and k are

Evaluate : int(1)/(sqrtx+sqrt(x-1))dx .

int e^(sqrtx) dx

int (1-x) sqrtx dx

int (a^sqrtx)/(sqrtx) dx equals

The value of int(e^(sqrtx))/(sqrtx(1+e^(2sqrtx)))dx is equal to (where, C is the constant of integration)

The value of int e^sqrtx/sqrtx(sqrtx + x) dx is equal to