Simplify `(sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)`

Prove the following identities: (sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+sin theta cos theta=1

Simplify: cos^(3)theta+sin^(3)theta=

Simplify (sin theta+cos theta+1)/(sin theta+cos theta-1)-(1+sin theta-cos theta)/(1-sin theta+cos theta)

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

The value of (sin^3 theta + cos^3 theta)/(sin theta+ costheta)+((cos^3 theta - sin^3 theta))/(cos theta - sin theta) is

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?

(3cos theta+cos3 theta)/(3sin theta-sin3 theta)=

(sin^(3)theta+cos^(3)theta)/(sintheta+costheta)+(sin^(3)theta-cos^(3)theta)/(sintheta-costheta)=

3. sin^(3)theta+cos^(3)theta=(sin theta+cos theta)(1-sin theta cos theta)