Simplify `3(sin^(4)theta+cos^(4)theta)-2(sin^(6)theta+cos^(6)theta)`

The value of the following is : 3(sin^(4)theta+cos^(4)theta)+2(sin^(6)theta+cos^(6)theta)+12sin^(2)thetacos^(2)theta

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

The value of 8(sin^(6)theta+cos^(6)theta)-12(sin^(4)theta+cos^(4)theta) is equal to

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

The value for 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1 is

Find the value of 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)-(sin^(2)theta+cos^(2)theta)^(2)

The value of the expression 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1 is

Find the value of 6(sin^(6)theta+cos^(6)theta)-9(sin^(4)theta+cos^(4)theta)+4

Which of the following values of a and b will make a(sin^(6)theta+cos^(6)theta)-b(sin^(4)theta+cos^(4)theta) independent of theta ?