`lim_(x->o)(x+absx)/(2x+3absx)`

lim_(x->0)x^3cos(2/x) =

lim_(x->2)(sqrt(x+7)-3)/(x-2)

If (lim)_(x->a)(x^3-a^3)/(x-a)=(lim)_(x->1)(x^4-1)/(x-1) , find all possible value o adot

Evaluate lim_(x-> 0) (tan3x-2x)/(3x- sin^2 x)

lim_(x -> oo) ((x-3)/(x+2))^x is equal to

Evaluate, lim_(xto0) (sin2x+3x)/(2x+tan3x) .

Let a= lim_(x->0)ln(cos2x)/(3x^2), b=lim_(x->0)(sin^(2)2x)/(x(1-e^x)), c=lim_(x->1)(sqrt(x)-x)/lnx

lim_(x->1)(x^4-3x^2+2)/(x^3-5x^2+3x+1)

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto1^+) (x([x]+absx)sin[x])/absx is equal to

let [x] denote the greatest integer less than or equal to x. Then lim_(xto0) (tan(pisin^2x)+(abs.x-sin(x[x]))^2)/x^2