`lim_(h->o)((x+h)^2-x^2)/h`

If f'(3)=2 , then lim_(h->0)(f(3+h^2)-f(3-h^2))/(2h^2) is

Let f(x)=3x^10-7x^8+5x^6-21x^3+3x^2-7 , then the value of lim_(h->0) (f(1-h)-f(1))/(h^3+3h)

Let lim_(x->oo) sqrt((x-cos^2x)/(x+sinx)) and I_2 = lim_(h->0^+) int_(-1)^1 hdx/(h^2+x^2) . Then

Prove that lim_(h to 0) (f(x+h)+f(x-h)-2f(x))/(h^(2))=f''(x)" (without using L' Hospital's rule)".

The value of lim_(h to 0) (f(x+h)+f(x-h))/h is equal to

Prove that lim_(x->0) (f(x+h)+f(x-h)-2f(x))/h^2 = f''(x) (without using L' Hospital srule).

If f(x) is derivable at x=3 and f'(3)=2 , then value of lim_(hto0)(f(3+h^(2))-f(3-h^(2)))/(2h^(2)) is less than

lim _(h -> 0) (sqrt(x+h) - sqrtx)/h

Evaluate: ("lim")_(h->0)((a+h)^2sin(a+h)-a^2sina)/h

Let f (x) =3x ^(10) -7x ^(8) +5x^(6) -21 x ^(3) +3x ^(2) -7 265 (lim _(htoo) (h ^(4) +3h^(2))/((f(1-h) -f (1))sin5h))=