Simplify `A=|[cos theta,0,sin theta],[0,1,0],[-sintheta,0,cos theta]|`

cos m theta-sin n theta=0

Find the inverse of A=[[cos theta,-sin theta,0sin theta,cos theta,00,0,1]]

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]

What is the inverse of the matrix A= ({:(cos theta, sin theta ,0),(- sin theta, cos theta,0),(0 , 0, 1):})

If cos2theta=0 , then |(0,costheta,sin theta),(cos theta, sin theta, 0),(sin theta, 0, cos theta)|^(2) is equal to…………

If I=[[1,0] , [0,1]] and B=[[0,1] , [-1,0]] and C=[[cos theta, sin theta] , [-sin theta, cos theta]] then C=

If the matrix [{:(cos theta,sin theta,0),(sin theta,cos theta,0),(0,0,1):}] is singular, then what is one of the values of theta ?

If theta, phi epsilon R , then the determinant Delta=|(cos theta, - sin theta, 1),(sin theta, cos theta, 1),(cos(theta+phi),-sin(theta+phi),0)| lies in the interval