`sin theta+cos theta=(5)/(6)`, find `sin theta-cos theta`

If 2 sin theta=5 cos theta , then (sin theta+cos theta)/(sin theta-cos theta) is equal to: यदि 2 sin theta=5 cos theta है, तो (sin theta+cos theta)/(sin theta-cos theta) का मान किसके बराबर होगा ?

Simplify: cos theta[cos theta sin theta-sin theta cos theta]+sin theta[sin theta-cos theta cos theta sin theta]

Simplify cos theta[(cos theta,sin theta),(-sin theta,cos theta)]+sin theta[(sin theta,-cos theta),(cos theta,sin theta)]

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

If (sin theta+cos theta)/(sin theta-cos theta)=3 then sin^4 theta-cos^4 theta=

If 5 tan theta =4, find the value of (5 sin theta - 3 cos theta)/(5 sin theta +2 cos theta)

If 3 cot theta = 4 , find the value of (5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta) .