`sin theta-cos theta=1/2` , find `sin theta+cos theta`

sin theta+cos theta=1 Find (sin theta-cos theta)^(2)

(1 + sin theta-cos theta) / (1 + sin theta + cos theta)

If sin theta+cos theta=1 then sin theta cos theta=

If sin theta+cos theta=1, then sin theta cos theta is equal to :

(1 + sin theta-cos theta) / (1 + sin theta + cos theta) =

((1 + sin theta-cos theta) / (1 + sin theta + cos theta)) ^ (2) = (1-cos theta) / (1 + cos theta)

If sin^(4) theta+cos^(4)theta=(1)/(2) , then find sin theta cos theta .

Prove each of the following identities : (sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta) = (2) /((sin^(2) theta - cos^(2) theta)) = (2) /((2sin^(2) theta -1))

(sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] "then " f (pi/7) is