`sin theta+cos theta=p`, find `sin theta-cos theta`

Simplify: cos theta[cos theta sin theta-sin theta cos theta]+sin theta[sin theta-cos theta cos theta sin theta]

If 2 sin theta=5 cos theta , then (sin theta+cos theta)/(sin theta-cos theta) is equal to: यदि 2 sin theta=5 cos theta है, तो (sin theta+cos theta)/(sin theta-cos theta) का मान किसके बराबर होगा ?

If sin theta+cos theta=1 then sin theta cos theta=

If sin theta+cos theta=1, then sin theta cos theta is equal to :

If (sin theta+cos theta)/(sin theta-cos theta)=3 then sin^4 theta-cos^4 theta=

If sin theta+cos theta=p and sec theta+cos ec theta=q find q(p^(2)-1)=

Prove each of the following identities : (i) (sin theta - cos theta)/(sin theta + cos theta) + ( sin theta+ cos theta)/(sin theta - cos theta) = (2)/((2 sin^(2) theta -1)) (ii) (sin theta + cos theta ) /(sin theta - cos theta) + ( sin theta - cos theta) /(sin theta + cos theta) = (2) /((1- 2 cos^(2) theta))

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] "then " f (pi/7) is

if sin theta+cos theta=p and sin^(3)theta+cos^(3)theta=q, then p(p^(2)-3)

[[ Simplify :cos thetacos theta,sin theta-sin theta,cos theta]]+sin theta[[sin theta,-cos thetacos theta,sin theta]]