Solve `sin^(8)theta-cos^(8)theta=(sin^(2)theta-cos^(2)theta)`

Prove the following identities: sin^(8)theta+cos^(8)theta=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)

(sin^(8)theta-cos^(8)theta)/(cos2theta(1+cos^(2)2theta))=?

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

Simplify sin^8theta-cos^8theta

The value of 8(sin^(6)theta+cos^(6)theta)-12(sin^(4)theta+cos^(4)theta) is equal to

Solve cos^(4)theta-sin^(4)theta=cos^2theta

solve 6sin^(2)theta-sin theta cos theta-cos^(2)theta=3

(2sin theta*cos theta-cos theta)/(1-sin theta+sin^(2)theta-cos^(2)theta)=cot theta