`sin^(-1)``(sin(pi/6))=?`

sin^(-1)(sin((pi)/(3)))=

Evaluate the following inverse trigonometric expression: sin^(-1)("sin"(7pi)/6)

sin(pi+pi/6)=

sin^(-1)(sin((7pi)/6)) is

Find the values of the following: sin^(-1)(sin((5 pi)/(6)))

Find the value of : (1) sin^(-1)(sin.(5pi)/(6)) (2) cos^(-1)(cos.(13pi)/(6)) (3) tan^(-1)(tan.(7pi)/(6))

The value of (1)/(pi){216sin^(-1)(sin(7 pi/6))+27cos^(-1)(cos(2 pi/3))+28tan^(-1)(tan(5 pi/4))+200cot^(-1)(cot(-(pi/4)))} must be Q

Principal value of sin^(-1)[sin((5pi)/(6))] is

sin^-1 (sin ((7pi)/6))= (A) (7pi)/6 (B) pi/6 (C) -pi/6 (D) none of these

The value of sin^(-1)(sin""(2pi)/(3))+cos^(-1)(cos""(7pi)/(6)) is