`sin^(-1)[sin^2(pi/4)]=?`

Evaluate the following: sin^(-1)(sin pi/4)

Given that "sin"^(-1)("sin""(3pi)/(4))=(2pi)/(k) ,then k=

If tan^(-1)(x^(2)+3|x|-4)+cot^(-1)(4 pi+sin^(-1)sin14)=(pi)/(2), then the value of sin^(-1)sin2x is (a)6-2 pi( b) 2 pi-6( c) pi-3 (d) 3-pi

If tan^(-1)(x^(2)+3|x|-4)+cot^(-1)(4pi+sin^(-1)sin14)=(pi)/(2) , then the value of sin^(-1)(sin2x) can be equal to

cos(pi/4-A)cos(pi/4-B)-sin(pi/4-A)sin(pi/4-B)=sin(A+B)

Find the value of sin^(-1)("sin"(2pi)/(3))+cos^(-1)("cos"(4pi)/(3))

sin(pi/4+A).sin(pi/4-A)=1/2 cos2A

sin^(2)(pi)/(4)+sin^(2)(3 pi)/(4)+sin^(2)(5 pi)/(4)+sin^(2)(7 pi)/(4)=2

sin (pi/2) = 2 sin(pi/4) cos (pi/4)

[ Number of solution of 4sin^(3)x-4sin^(2)x-sin(pi-x)+1=0;x in[0,pi]; is [ (1) 1, (2) 2 (3) 3, (4) 4]]