` int (3x^2+1) /((x-2)(x^2+4))dx`

If int(2x^2+3)/((x^2-1)(x^2+4))dx=alog((x-1)/(x+1))+btan^(- 1) (x/2)+C then the values of a and b are respectively (A) 1/2,1/2 (B) 1,1 (C) 1/2,1 (D) None

int(3x+1)/((x-2)^2(x+2))dx

Evaluate int (3x^2+4x-5)/((x^2-1)(x+2))dx

int (3x^2 - 4)x dx

int(3x+1)/((x+2)(x-2)^(2))dx

int (1+3x^2)/(x(1+x^2)) dx

int(3x^(2)+1)/(x(x^(2)+1))dx

int x/(3x^2 + 4) dx

int (dx)/((x+1)(2x+1)) (ii) int (x-1)/((x-2)(x-3)) dx .

int(3dx)/((x^(2)+1)(x^(2)+4))=