Recommended Questions
- sin^2 ((2pi)/3) + cos^2 ((5pi)/6) - tan^2 ((3pi)/4) = ?
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- Statement I : sin^2pi/8+sin^2(3pi)/8+sin^2(5pi)/8+sin^2(7pi)/8=2 State...
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- cos^-1 {-sin((5pi)/6)}= (A) - (5pi)/6 (B) (5pi)/6 (C) (2pi)/3 (D) -(2p...
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- sin((13pi)/3)sin((8pi)/3)+cos((2pi)/3)sin((5pi)/6)=1/2
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- Consider the following : 1. tan((pi)/(6)) 2. tan((3pi)/...
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- sin^(2)""(2pi)/(3)+ cos^(2)""(5pi)/6-tan^(2)""(3pi)/4=
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- 3[sin^(4)(3pi//2-alpha)+sin^(4)(3pi+alpha)]-2[sin^(6)(pi//2+alpha)+sin...
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- I. Sin^(-1)("sin"(2pi)/3)=(2pi)/3 II. Cos^(-1)("cos"(5pi)/4)=(5pi)/4
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- Show that :(i) sin^(-1) [ sin. (3pi)/4] != (3pi)/4 (ii) tan^(-1) ...
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