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solve : 2x+3y=8 and 2x=2+3y...

solve : 2x+3y=8 and 2x=2+3y

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For hyperbola whose center is at (1,2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1, the equation of the hyperbola passing through (2,4) is (2x+3y-5)(x+2y-8)=40(2x+3y-8)(x+2y-8)=40(2x+3y-8)(x+2y-5)=30 these