`int_3^5(dx)/((x)^2-1)`

int_(3)^(5) (3dx)/(x(x-1)(x+1))

(i) int_1^3 (3x)/(9x^2-1) dx (ii) int_2^3 x/(x^2+1) dx

(i) int_0^1 (dx)/sqrt(1-x^2) (ii) int_0^1 (dx)/sqrt(1+x^2) (iii) a int_1^sqrt3 (dx)/(1+x^2) b int_0^1 (dx)/(1+x^2) (iv) int_0^(2//3) (dx)/(4+9x^2) (v) int_0^1 x/(x^2+1)dx (vi) int_2^3 x/(x^2+1) dx

int (dx)/((x+1)(2x+1)) (ii) int (x-1)/((x-2)(x-3)) dx .

int(e^(x))/((1+x)^(3))dx-int(e^(x))/(2(1+x)^(2))dx=

Evaluate: (i) int(x^(2)+x+5)/(3x+2)dx (ii) int(2x+3)/((x-1)^(2))dx

int(5x+3)/((x+1)^(2))dx

int_(2)^(5)(1)/((2+3x))dx is -

int(2x^(2)-3x-3)/((x-1)(x^(2)-2x+5))dx