`int 1/(8-3x+2x^2) dx`

int(1)/(8+3x-x^(2))dx

(i) int (3x^2)/(x^6+1) dx (ii) int (3x)/(1+2x^4) dx

int (2x)/(x^2+3x+2) dx (ii) int x/((x+1)(x+2)) dx

int(5x-1)/(3x^2+x+2)dx=

int(1)/(3x^(2)-8)dx

(i) int_1^3 (3x)/(9x^2-1) dx (ii) int_2^3 x/(x^2+1) dx

int ((x+1)/(2x+3))dx

Evaluate: int1/(sqrt(8+3x-x^2))\ dx

(i) int_0^1 (dx)/sqrt(1-x^2) (ii) int_0^1 (dx)/sqrt(1+x^2) (iii) a int_1^sqrt3 (dx)/(1+x^2) b int_0^1 (dx)/(1+x^2) (iv) int_0^(2//3) (dx)/(4+9x^2) (v) int_0^1 x/(x^2+1)dx (vi) int_2^3 x/(x^2+1) dx

int1/sqrt(8+2x-x^(2))dx=