`xy (dy/dx) = (x + y)^(2)`

Solve the differential equation : xy dy/dx = x^2 + 2y^2

xy (dy)/(dx) =x^(2) +2y^(2)

xy (dy)/(dx) = x^(2) + 2y^(2) , y(1) = 0

2xy(dy)/(dx)=x^(2)+y^(2)

xy(dy)/(dx)=y+2

Solve the following differential equations: xy(dy)/(dx)=x^(2)+y^(2)

Find the particular solution of the differential equation xy(dy)/(dx) =(x+2) (y+2), it being given that y = -1 when x = 1.

For the differential equation : xy (dy)/(dx)=(x+2)(y+2) , find the solution of curve passing through the point (1, -1).