`e^x(dy)/(dx) + 2x = 0`

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If x log_(e) (log _(e) x) - x^(2) + y^(2) = 4 (y gt 0) , then (dy)/(dx) at x = e is equal to

If x^(2) = e^(x-y) , then (dy)/(dx) at x = 1 is ……..

(dy)/(dx) + 2y = e ^(-2x) sinx , given that y=0 when x = 0

If y=x^(x^(2)), then (dy)/(dx) at x=e is

e ^ (y) (dy) / (dx) + x ^ (3) cos x ^ (2) = 0

If e^(y) +xy = e , the ordered pair ((dy)/(dx),(d^(2)y)/(dx^(2))) at x = 0 is equal to

(dy)/(dx) -y =e^(x ) " when" x=0 and y=1

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Solve the following differential equation: x(dy)/(dx)-y-2x^3=0 i.e., (dy)/(dx)-y/x=2x^2