(dy/dx) = ? xy + yx = 1...

(dy/dx) = ?
`xy + yx = 1`

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Find (dy)/(dx) if xy - x = 1.

(dy) / (dx) = e ^ (xy) (e ^ (yx) -e ^ (y))

yx (dy) / (dx) = a (y ^ (2) + (dy) / (dx))

(dy)/(dx)=x+xy

Find (dy)/(dx) , if xy = log (xy)

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The solution of the ( dy )/(dx) = (xy+y)/(xy+x) is :

(dy)/(dx)+xy=xy^(3)

(dy)/(dx)=(xy+y)/(xy+x)

y^(2)-x^(2) (dy)/(dx) = xy(dy)/(dx)

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