`int_(0)^(log 2)e^(2x)dx`

int_(0)^(log 2)(e^(x))/(1+e^(x))dx=

Evaluate :int_(0)^(1)x log(1+2x)dx

Evaluate : int_0^(ln2)x e^(-x)dx

Evaluate int_(5)^(7)ln(x-3)^(2)dx+2int_(0)^(1)ln(x+4)^(2)dx

Suppose that f,f^prime and f prime prime are continuous on [0, ln 2] and that f (0) = 0, f prime(0) = 3, f(In 2) = 6,f prime(ln 2) = 4 and int_0^(ln 2) e^(-2x)*f(x)dx=3. Find the value of int_0^(ln2) e^(-2x)*f prime prime(x)dx.

What is int_(0)^(2) e^(ln) x dx equal to ?

int_(0)^(16)(log_(e )x^(2))/(log_(e )x^(2)+log_(e )(x^(2)-44x+484))dx is equal to

" (2) "int_(1)^(2)(log e^(x))/(x^(2))dx

If I_(1)=int_(e)^(e^(2))(dx)/(ln x) and I_(2)=int_(1)^(2)(e^(x))/(x)dx

If the value of the integral int_(1)^(2)e^(x^(2))dx is alpha, then the value of int_(e)^(e^(4))sqrt(ln x)dx is: