Find the value of x :

`log_( k )x times log_( 5 )k` = 3

If x = log_(3) 4 " and " y = log_(5) 3 , find the value of log_(3) 10 " and " log_(3) (1 . 2) in terms of x and y .

Find the values of x satisfying the inequalities: log_(2)(x^(2)-24)>log_(2)(5x)

Find the value of x,log_(4)(x+3)-log_(4)(x-1)=log_(4)8-2

If x=log_(3)4 and y=log_(5)3, find the value of log_(3)10 and log_(3)backslash(6)/(5) in terms of x and y.

Find the value of lim_(xto0^(+)) (3(log_(e)x)^(2)+5log_(e)x+6)/(1+(log_(e)x)^(2)).

Find the value of x satisfying the equation,sqrt((log_(3)3sqrt(3)x+log_(x)3sqrt(3)x)*log_(3)x^(3))+sqrt(((log_(3)(3sqrt(x)))/(3)+(log_(x)(3sqrt(x)))/(3))*log_(3)x^(3))=2

Find the value of x satisfying the equation,sqrt((log_(3)(3x)^((1)/(3))+log_(x)(3x)^((1)/(3)))log_(3)(x^(3)))+sqrt((log_(3)((x)/(3))^((1)/(3))+log_(x)((3)/(x))^((1)/(3)))log_(3)(x^(3)))=2

The value of x satisfying log_(3)4 -2 log_(3)sqrt(3x +1) =1 - log_(3)(5x -2)