`(2x+5)^2-(2x-5)^2`

The measure of angles of a hexagon are x^0,\ (x-5)^0,\ (x-5)^0,\ (2x-5)^0,\ (2x-5)^0,\ (2x+20)^0dot Find the value of xdot

(x^2-1)/(2x+5)<3

(x^2-1)/(2x+5)<3

Solve: (x^2-2x+5)/(3x^2-2x-5)>1/2 .

Find x , if (2/5)^(-3)x\ (2/5)^(15)=(2/5)^(2+3x)

Simplify: (2x^2+3x-5)(3x^2-5x+4)

Evaluate: int(2x+5)/(x^2-x-2)\ dx

Factorise : (2x^(2)+5x)(2x^(2)+5x-19)+84

Evaluate lim_(xtoa) ((2+x)^(5//2)-(a+2)^(5//2))/(x-a)

Factorize : (1) 7(2x+5)+3(2x+5) , (2) (x+2)y+(x+2)x , (3) 5a(2x+3y)-2b(2x+3y) , (4) 8(5x+9y)^2+12(5x+9y)