`(2x+y)(2x-y)`

For x = 2 and y = -3, verify the following: x^(2)-y^(2)=(x+y)(x-y)

Simplify: x^2(x+2y)(x-3y)

The factors of x^3-x^2y-x y^2+y^3 are (a (x+y)(x^2-x y+y^2) (b) (x+y)(x^2+x y+y^2) (c) (x+y)^2(x-y) (d) (x-y)^2(x+y)

If xa n dy are of same sign, then the value of (x^3)/2cos e c^2(1/2tan^(-1)x/y)+(y^3)/2sec^2(1/2tan^(-1)y/x) is equal to (x-y)(x^2+y^2) (b) (x+y)(x^2-y^2) (x+y)(x^2+y^2)dot (d) (x-y)(x^2-y^2)

The differential equation of all circle in the first quadrant touch the coordinate is (a) (x-y)^(2)(+y')^(2))=(x+yy')^(2) (b) (x-y)^(2)(+y')^(2))=(x+y')^(2) ( c ) (x-y)^(2)(+y')=(x+yy')^(2) (d) None of these

Evaluate : (2x - 5y)(2x+ 3y) for x = 2 and y = 3.

A function f: R rarr R" satisfies sin x cos y "(f(2x+2y)-f(2x-2y))= cos x sin y (f(2x+2y)+f(2x-2y)). " If "f'(0)=(1)/(2), then

Solve the following system of equations: 3/(x+y)+2/(x-y)=2,\ \ \ \ 9/(x+y)-4/(x-y)=1

The solution of (dy)/(dx)=((x-1)^2+(y-2)^2tan^(- 1)((y-2)/(x-1)))/((x y-2x-y+2)tan^(- 1)((y-2)/(x-1))) is equal to

Factorise : (vi) 15 (2x - y)^(2) - 16 (2x -y) - 15