`sin y=n sin((pi)/(4)+y)`

The transverse wave represented by the equation y = 4 "sin"((pi)/(6)) "sin"(3x - 15 t) has

Plot y=sin(x+(pi)/(4)) and y =sin(x-(pi)/(4)) .

Sketch the graph of the following pairs of functions on the same axes: y=sinx ,\ y=sin(x+pi/4)

cos((pi)/(4)-x)cos((pi)/(4)-y)-sin((pi)/(4)-x)sin((pi)/(4)-y)=sin(x+y)

Draw the graph of the functions on the same axes: y= sin x and y= sin (x- pi/4)

The value of sin pi/n + sin (3pi)/n+ sin (5pi)/n+... to n terms is equal to

Find the incentre of a triangle formed by the lines x "cos" (pi)/(9) + y "sin" (pi)/(9) = pi, x "cos" (8pi)/(9)+ y "sin" (8pi)/(9) = pi " and x "cos" (13pi)/(9) + y "sin" ((13pi)/(9)) = pi.

In DeltaABC, prove that: a) sin(A/2)+sin(B/2) +sin(C/2)= 1+4sin((pi-A)/4)sin((pi-B)/4).sin((pi-C)/4)

Sketch the graph : y=2 sin (x - pi/4)

Evaluate sin(pi/n)+sin((3pi)/n)+sin((5pi)/n)+........ to n terms.