(ii) `[(1/2)^-2times(1/2)^-3times(1/2)^7]`

Find the value of. (i) (3^@+4^(-1)) xx 2^2 (ii) (2^(-1)xx 4^(-1))-: 2^(-1) (iii) (1/2)^-2 + (1/3)^-2 + (1/4)^-2 (iv) (3^-1 + 4^-1+ 5^(-1))^0 (v) {((-2)/3)^-2}^2

Simplify (i) {(1/3)^(-2) - (1/2)^(-3)} -: (1/4)^(-2). (ii) (5/8)^(-7) xx (8/5)^(-5).

Show ((-8)/(7))times[(1)/(2)times((-4)/(3))]=[((-8)/(7))times(1)/(2)]times((-4)/(3))

Evaluate: (-2) times (-3) times (-1) times (-4) times (-7)

Simplify the following : (1""7/8 div 1""1/2) times (8""1/3 div 1""1/2)

Evaluate each of the following: (i)\ (2/(11))^4\ xx\ \ ((11)/3)^2\ xx\ \ (3/2)^3 (ii)\ (1/2)^5\ xx\ ((-2)/3)^4xx\ (3/5)^(-1)

Evaluate the following : (i) 2/3 times 9/16" (ii) " 3/7 times 1""3/4 .

Evaluate: [(-2) times (7)]-[(-7) times 2]

Evaluate the following : (i) 2/5 times 3/7" (ii) " 3/5 times 8/9" (iii) " 7 times 1""2/3 .

Simplify the following: (i)\ (5^(n+3)-\ 6\ xx\ 5^(n+1))/(9\ xx\ 5^n-2^2\ xx\ 5^n) (ii)\ (6(8)^(n+1)+\ 16(2)^(3n-2))/(10(2)^(3n+1)-7\ (8)^n)