`a^2+b^2/4+c^2/9-ab+(bc)/3-2/3ca`

Factorise by taking at the common factors: (i) ab(a^(2) + b^(2) -c^(2))-bc(c^(2)-a^(2) - b^(2)) +ca(a^(2) + b^(2)-c^(2)) (ii) 2x(a-b) +3y(5a-5b) + 4z(2b-2a)

Find the product : (i) (a+2b+4c)(a^(2)+4b^(2)+16c^(2)-2ab-8bc-4ca) (ii) (3x-5y-4)(9x^(2)+25y^(2)+15xy+12x-20y+16) (iii) (2-3b-7c)(4+9b^(2)+49c^(2)+6b-21bc+14c) (iv) (sqrt(2)a+2sqrt(2)b+c)(2a^(2)+8b^(2)+c^(2)-4ab-2sqrt(2)bc-sqrt(2)ac)

If a = 2, b = 3 and c = -2, find the value of a^(2)+b^(2)+c^(2)-2b-2bc-2ca+3abc

Resolve into linear factors a^2+b^2+c^2-ab-bc-ca

In any DeltaABC , prove that : a^2 +b^2 +c^2 = 2 (bc cos A + ca cos B + ab cos C) .

Fill in the blanks: 2abc^2+3ab^2c-4ab+3bc-2ca-2=2abc^2+3bc-2ca-2- _________

Find the product (2a-3b-2c)(4a^(2)+9b^(2)+4c^(2)+6ab-6bc+4ca) .

What should be subtracted from a^2+b^2+c^2-ab-bc-9 to get ab+bc+ca+abc+9

If a= 2, b= 3 and c= 4, find the value of : (ab + bc + ca- a^(2) -b^(2)-c^(2))/(3abc-a^(3)-b^(3)-c^(3)) , using suitable identity

Using column method , add ab+2bc - ca and 2ab - bc -ca and subtract 4ab + 5bc - 3ca