Evaluate :

`lim_( n -> 0 ) ( e^( n/2 ) - 1 )/n`

Evaluate : lim_( x -> 0 ) ( (e^N - sinx - 1) )/a

Evaluate : lim_( n -> ∞ )( 1 + 1/n )^n is equal to

Evaluate lim_ (n rarr oo) [(1+ (1) / (n)) 91+ (2) / (n)) .... (1+ (n) / (n))] ^ ((1) /(a))

Evaluate: lim_ (n rarr oo) (1 ^ (4) + 2 ^ (4) + 3 ^ (4) + ... + n ^ (4)) / (n ^ (5)) - lim_ (n rarr oo) (1 ^ (3) + 2 ^ (3) + ... + n ^ (3)) / (n ^ (5))

Evaluate: lim_ (n rarr oo) (1 ^ (4) + 2 ^ (4) + 3 ^ (4) + ... + n ^ (4)) / (n ^ (5)) - lim_ (n rarr oo) (1 ^ (3) + 2 ^ (3) + ... + n ^ (3)) / (n ^ (5))

evaluate lim_ (n rarr oo) ((e ^ (n)) / (pi)) ^ ((1) / (n))

Evaluate lim_ (n rarr oo) (1) / (n) sum_ (r = n + 1) ^ (2n) log_ (e) (1+ (r) / (n))

Evaluate lim_(nrarroo) [1/(n+1) + 1/(n+2) + 1/(n+3) +…+ 1/(2n)]

Evaluate lim_(nrarroo) [1/(n+1) + 1/(n+2) + 1/(n+3) +…+ 1/(2n)]