1.3.5.7.9...(2n-1) =...

`1.3.5.7.9...(2n-1) = `

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If n is a natural number then show that 1.3.5.7…..(2n-1) = ((2n)!)/(2^n n!)

The A.M of the observations 1.3.5,3.5.7,5.7.9,...,(2n-1)(2n+1)(2n+3) is

The A.M.of the observations 1.3.5,3.5.7,5.7.9,......,(2n-1)(2n+1)(2n+3) is (AA n in N)

1.3+3.5+5.7+......+(2n-1)(2n+1)=(n(4n^(2)+6n-1))/(3)

1.3.5.7+3.5.7.9+...

Prove that 1+3+5+7......+(2n+1)=(n+1)^(2)

1xx3xx5xx7xx9xx...xx(2n-1)=

1.3.5.7+3.5.7.9+.....

Find the sum of n terms of the series 1.3.5.+3.5..7+5.7.9+...

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