Prove
`cos^2 theta - sin^2 theta =cos^4 theta - sin^4 theta`

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है:

Solve cos^(4)theta-sin^(4)theta=cos^2theta

Prove each of the following identities : (cos theta) /((1- tan theta)) - (sin^(2) theta)/((cos theta - sin theta)) = (cos theta + sin theta)

Prove that : cos^(4)theta - cos^(2)theta = sin^(4)theta - sin^(2) theta

Prove (cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

Prove that sin theta cos^(3)theta - cos theta sin^(3) theta = (1)/(4) sin 4 theta .

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

Prove that :(cos theta-sin theta)/(cos theta+sin theta)=sec2 theta-tan2 theta

Prove that (cos theta-sin theta)/(cos theta+sin theta)=sec2theta-tan2theta

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta