`dy/dx=2^(sinx)`

Find y(pi) if y(0)=7 and (dy)/dx=2(y-2sinx-10)x+2cosx

"If "y=sqrt(cosx+sqrt(cosx+sqrt(cosx+...oo)))", prove that "(dy)/(dx)=(sinx)/((2y-1)).

Order and degree of the differential equation (dy)/(dx)=(2sinx+3)/((dy)/(dx)) respectively are

ysinx dy/dx=(sinx-y^2)cosx

Solve: (secx)(dy)/(dx)=y+sinx

Degree and order xy(d^(2)y)/(dx^(2))+((dy)/(dx))^(3)-y(dy)/(dx)=sinx

If y=sqrt(cos x+sqrt(cos x +sqrt(cos x+....oo))) " then prove that " dy/dx = sinx /(1-2y).

Let y=y(x) be the solution of the differential equation (dy)/(dx)=2(y+2sinx-5)x-2cosx such that y(0)=7 . Then y(pi) is equal to

Find (dy)/(dx) , when: y=x^(x)-2^(sinx)

Find (dy)/(dx), when: y=(logx)^(sinx)