Recommended Questions
- सिद्ध कीजिये abs((1,bc,b+c),(1,ca,c+a),(1,ab,a+b))=abs((1,a,a^2),(1,b,...
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- det[[1,bc,bc(b+c)1,ca,ca(c+a)1,ab,ab(a+b)]]=0
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- |{:(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b)):}|=0
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- |(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b))|=
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- |(a^(2)+1,ab,ac),(ab,b^2+1,bc),(ca,cb,c^2+1)|= 1 + a^2 + b^2 + c^2.
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- Prove that |(1,a^2,bc),(a,b^2,ca),(1,c^2,ab)|=(a-b)(b-c)(c-a)
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- বিস্তত না করে দেখাও যে,:abs[[1,a,a^2],[1,b,b^2],[1,c,c^2]]=abs[[1,a,b...
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- If ab + bc + ca = 0, then the value of 1/(a^2 - bc) + 1/(b^2 - ca) + 1...
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- বিস্তৃত না করে প্রমাণ করো যে, abs((1,bc,b+c),(1,ca,c+a),(1,ab,a+b))=ab...
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