`2x+3y=5 , 2x-3y=5`

Find for values of x and y 3x+2y=5 2x-3y=7

The equation 2x+y=5, x+3y =5, x-2y=0 have :

On comparing the ratios (a_1)/(a_2),(b_1)/(b_2) and (c_1)/(c_2) , find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x+2y=5; 2x-3y = 7 (ii) 2x-3y=8 ; 4x-y=9 (iii) 3/2x+5/3y=7 ; 9x-10y=14 (iv) 5x-3y=11 ; -10x+6y = -22 (v) 4/3 x +2y=8 ; 2x+3y = 12

If 2x+3y=5, 2y+z=3, and x+5y+z=3 , then x =

Find the value of x and y : 2x+3y=5,3x+y=4

Show that the lines 2x + 5y = 1, x - 3y = 6 and x + 5y + 2 = 0 are concurrent.

Find the equation of the line through the intersection of 5x-3y=1 and 2x-3y -23= 0 and perpendicular to the line 5x - 3y -1 =0 .

Find the angle between the straight lines joining the origin to the point of intersection of 3x^2+5x y-3y^2+2x+3y=0 and 3x-2y=1

Find the angle between the straight lines joining the origin to the point of intersection of 3x^2+5x y-3y^2+2x+3y=0 and 3x-2y=1