`sqrt 2x = sqrt 8`

Prove that sqrt ( 2 + sqrt (2 + sqrt (2 + 2 cos 8 theta))) = 2 cos theta, where theta in [ (-pi)/(8), (pi)/(8)]

Solve the following in equations : i) sqrt(x+2) = sqrt(8-x^(2))

(v) Solve for x and y if (sqrt2 x+sqrt 3 y)=0 and (sqrt3 x- sqrt8 y)=0

Solve the following quadratic equations : (i) 9x^(2) - 8x+2=0 (ii) sqrt7 x^(2) +x+ sqrt7=0 (iii) 2sqrt3x^(2) -sqrt2 x + 3sqrt3 =0

If 0 (a) sqrt(x)-\ sqrt(y)=\ sqrt(x-y) (b) sqrt(x)+\ sqrt(x)=\ sqrt(2x) (c) xsqrt(y)=ysqrt(x) (d) sqrt(x y)=\ sqrt(x)\ sqrt(y)

Find other zeroes of the polynomial p(x)=3x^(4)-4x^(3)-10x^(2)+8x+8 , if two its sources are sqrt2 and -sqrt2 .

Solve the inequation sqrt(x+2) gt sqrt(8-x^(2)) .

The value of x, x in (2,oo) where f (x) = sqrt(x sqrt(8x-16))+ sqrt(x- sqrt(8x-16)) is not differentiable is:

the length of intercept made by the line sqrt2x-y-4sqrt2=0 on the parabola y^2=4x is equal to (a) 6sqrt3 (b) 4sqrt3 (c) 8sqrt2 (d) 6sqrt2

Find other zeros of the polynomial p(x)=3x^(4)-4x^(3)-10x^(2)+8x+8 if two of its zeroses are sqrt2 and -sqrt2