`sqrt(x^(2))=16`

Find the range of each of the following function: f(x)=sqrt(16-x^(2))

Find the domain of the following functions: f(x)=sqrt(sinx)+sqrt(16-x^(2))

int(dx)/(x^(2)sqrt(16-x^(2))) has the value equal to

Find the domain and range of f(x)=sqrt(4-16x^(2)) .

Domain of the function f(x) = sin^(-1) [1 + cos x]- sqrt(16-x^(2)) ([.) denotes the greatest integer function) is

Find the range of the function f(x)=3 sin (sqrt((pi^(2))/(16)-x^(2))).

The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axis is

Find the domain of definition of the following functions : (i) f(x) = log_(10) sin (x-3) + sqrt(16 - x^(2))

int (dx)/(sqrt(16-9x^(2)))

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .