Recommended Questions
- int(-pi/2)^(pi/2) sin^2 xcos^4 x dx
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- int (0) ^ ((pi) / (2)) (sin x) / (sin x + cos x) dx = int (0) ^ ((pi) ...
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- int(-pi/2)^( pi/2)(dx)/([x]+[sin x]+4)
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- Evaluate int(-(pi)/(2))^(pi/2) sin^(3)xcos^(2)x(sinx+cosx)dx.
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- int(0)^(pi//2) sin^(4)xcos^(3)dx is equal to :
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- int(-pi//2)^(pi//2) sin^(2)x cos^(2) x(sin xcos x)dx=
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- int(-pi//4)^(pi//4)sin^(2)x dx=
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- int(0)^(pi//2)sin^(4)xcos^(5)x dx=
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- int(0)^(pi//2)(sin xcos x) / (1+ sin^(4) x ) dx =
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