`int (ycosx+siny+y)dx`

The solution of the differential equation x cos y (dy)/(dx)+siny =1 is (Here, x gt0 and lambda is an arbitrary constant)

The solution of the differential equation ycosx.dx=sinx.dy+xy^(2)dx is (where, c is an arbitrary constant)

What is the value of tan y if (siny+cosy)/(siny-cosy)=3 ?

If y=4cos4x find int y dx

sec x dy +cosec y dx=0 A) cos x-sin xy=c B) cos x+siny=c C) sinx-cos y=c D) sin(x-y)=c

Find the general solution of each of the following differential equations: cosx(1+cosy)dx -siny (1+sinx)dy =0

int{f(x)+-g(x)}dx=int f(x)dx+-int g(x)dx

(cosx)^(y)=(siny)^(x)

If y=xcosy+ycosx, then find (dy)/(dx)