`int 1/(acosx+bsinx)dx`

int((acosx-bsinx)dx)/((a sin x+b cos x)^(2))

int((acosx-bsinx)dx)/((a sin x+b cos x)^(2))=

int 1/(1+cosx) dx=

int 1/(1+cosx) dx

int(acosx-bsinxdx)/(a sin x+b cos x)

int 1/secx dx

The integral int (dx)/(acosx+bsinx) is of the form (1)/(r )ln[tan((x+alpha)/(2))] What is r equal to ?

The integral int (dx)/(acosx+bsinx) is of the form (1)/(r )ln[tan((x+alpha)/(2))] What is alpha equal to ?

Evaluate the following integrals: int(dx)/((acosx+bsinx)^(2)),agt0andbgt0

7*int(acosx-bsinx)/((a sin x+b cos x)^(2))dx