(1+sinθ)(1-sinθ) = 2

If (sinθ/(1+ cosθ)) + ((1 +cosθ)/sinθ) = 4/sqrt3 0^circ lt θ lt 90^circ , then the value of (tanθ + secθ)^(-1) is : यदि (sinθ/(1+ cosθ)) + ((1 +cosθ)/sinθ) = 4/sqrt3 0^circ lt θ lt 90^circ ,, तो (tanθ + secθ)^(-1) का मान है :

Prove the following trigonometric identities: sinθ/(1+cosθ) + (1+cosθ)/sinθ = 2/sinθ

The value of ((sinθ -cosθ )(1 + tanθ + cotθ ))/(1+sinθ cosθ ) = ? ((sinθ -cosθ )(1 + tanθ + cotθ ))/(1+sinθ cosθ ) का मान है :

(sinθ - 2sin^3θ)/(2cos^3θ - cosθ) = tanθ

The value of ( 1 + cotθ – cosecθ ) ( 1 + cosθ + sinθ )secθ = ? ( 1 + cotθ – cosecθ ) ( 1 + cosθ + sinθ )secθ का मान है :

x = a(θ - sinθ), y = a(1 + cosθ) Find dy/dx

If ((sinθ−cosecθ)(cosθ−secθ))/(tan^(2)θ -sin^(2)θ) = r^3 , then r=? यदि ((sinθ−cosecθ)(cosθ−secθ))/(tan^(2)θ -sin^(2)θ) = r^3 है तो r बराबर हैः

If 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ , then the value of (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) is: यदि 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ है, तो (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) का मान है:

Find the general solution of: Cos^2θ - Sinθ - 1/4 = 0

If x=a(θ−sinθ)andy=a(1+cosθ) then prove that dy/ dx ​ =−cot( θ/2 ​ )