`r=a (1 + sinθ) and r=a (1 - sinθ)`
find `(dr)/(d theta)`for each

Solve (dr)/(d theta)= cos theta .

x = a(θ - sinθ), y = a(1 + cosθ) Find dy/dx

Find the values of theta which satisfy r sin theta=3 and r=4 (1 + sin theta), 0 <= theta <= 2 pi

If r=1-costheta," then "r(d theta)/(dr)=

If x = r cos theta, y = r sin theta, r =a(1+cos theta) then find (dy)/(dx)

If theta in [0,3 pi] and r in R . Then , find the pair of ( r , theta ) satisfying 2 sin theta = r^(4)- 2r^(2)+3 .

Find (dr)/(dn) , r=n^(sqrt(n))

If P(5,r)=P(6,r-1),f in dr