`int(f'(ax+b)dx`

intsec(ax+b)dx

The value of int((ax^2-b)dx)/(xsqrt(c^2x^2-(ax^2+b)^2)) is equal to

Evaluate int\(ax+b)\dx

int (ax +b)^(2)dx

By substitution: Theorem: int (ax+b)^n dx = (ax+b)^(n+1)/(a(n+1))

Iff(2-x)=f(2+x)a n df(4-x)=f(4+x) for all xa n df(x) is a function for which int_0^2f(x)dx=5,t h e nint_0^(50)f(x)dx is equal to (a)125 (b) int_(-4)^(46)f(x)dx (c) int_1^(51)f(x)dx (d) int_2^(52)f(x)dx

intsqrt (ax+b)dx

Let overset(a)underset(0)int f(x)dx=lambda and overset(a)underset(0)int f(2a-x)dx=mu . Then, overset(2a)underset(0)int f(x) dx equal to

Find int(dx)/(ax+b)

If f(a+b-x)=f(x),\ then prove that \ int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dx